(-16x^2)-22x+220=0

Solution for (-16x^2)-22x+220=0 equation:

(-16x^2)-22x+220=0

We get rid of parentheses

-16x^2-22x+220=0

a = -16; b = -22; c = +220;
Δ = b2-4ac
Δ = -222-4·(-16)·220
Δ = 14564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14564}=\sqrt{4*3641}=\sqrt{4}*\sqrt{3641}=2\sqrt{3641}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{3641}}{2*-16}=\frac{22-2\sqrt{3641}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{3641}}{2*-16}=\frac{22+2\sqrt{3641}}{-32}
$